The standard reduction potentials at 25^o tex | vedclass

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(D) The strength of an oxidizing agent is directly proportional to its standard reduction potential $(E^o_{red})$.Greater the value of $E^o_{red}$,str

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$Mg^{2+}$

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(D) The strength of an oxidizing agent is directly proportional to its standard reduction potential $(E^o_{red})$.Greater the value of $E^o_{red}$,stronger is the oxidizing agent.The given reduction potentials are:$E^o(Li^{+}/Li) = -3.05 \ V$$E^o(Ba^{2+}/Ba) = -2.73 \ V$$E^o(Na^{+}/Na) = -2.71 \ V$$E^o(Mg^{2+}/Mg) = -2.37 \ V$Comparing these values,$-2.37 \ V$ is the highest value.Therefore,$Mg^{2+}$ is the strongest oxidizing agent among the given species.

The standard reduction potentials at $25^o \text{C}$ for $Li^{+}/Li$,$Ba^{2+}/Ba$,$Na^{+}/Na$,and $Mg^{2+}/Mg$ are $-3.05 \ V$,$-2.73 \ V$,$-2.71 \ V$,and $-2.37 \ V$ respectively. Which of the following is the strongest oxidizing agent?

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