The resistance of a $0.2 \, M$ electrolyte solution is $50 \, \Omega$. The specific conductivity of the solution is $1.3 \, S \, m^{-1}$. If the resistance of a $0.4 \, M$ solution of the same electrolyte is $260 \, \Omega$,what is its molar conductivity?

Resistance of a conductivity cell (cell constant $129 \; m^{-1}$) filled with $74.5 \; ppm$ solution of $KCl$ is $100 \; \Omega$ (labelled as solution $1$). When the same cell is filled with $KCl$ solution of $149 \; ppm$,the resistance is $50 \; \Omega$ (labelled as solution $2$). The ratio of molar conductivity of solution $1$ and solution $2$ is i.e.,$\frac{\wedge_{1}}{\wedge_{2}} = x \times 10^{-3}$. The value of $x$ is (Nearest integer). Given,molar mass of $KCl$ is $74.5 \; g \; mol^{-1}$.

The resistance of a conductivity cell of $0.1 \ M$ $KCl$ solution is $120 \ \Omega$ and conductivity is $1.64 \times 10^{-4} \ S \ cm^{-1}$. What is the value of cell constant (in $cm^{-1}$)?

The resistance of a $0.5 \, M$ solution of an electrolyte in a cell was found to be $50 \, \Omega$. If the electrodes in the cell are $2.2 \, cm$ apart and have an area of $4.4 \, cm^2$,then the molar conductivity (in $S \, m^2 \, mol^{-1}$) of the solution is:

$A$ conductivity cell is filled with $0.01 \ M \ KCl$ and gives a resistance of $484 \ \Omega$. The conductivity of the solution is $0.00141 \ \Omega^{-1} \ cm^{-1}$ at $25^{\circ}C$. What is the cell constant (in $cm^{-1}$)?

What is ionic conductivity? On what factors does it depend?