The values of $\mu^{\infty}$ for $NH_4Cl$,$NaOH$,and $NaCl$ are $129.8$,$248.1$,and $126.4 \ \Omega^{-1} \ cm^{2} \ mol^{-1}$ respectively. Calculate $\mu^{\infty}$ for $NH_4OH$ solution.
- A$285.3$
- B$278.6$
- C$251.5$
- D$243.9$
Explore More
Similar Questions
The dissociation constant of acetic acid is $1.6 \times 10^{-5}$ and molar conductance at infinite dilution is $380 \times 10^{-4} \, S \, m^2 \, mol^{-1}$. The specific conductance of $0.01 \, M$ acid solution is
Medium
View SolutionKohlrausch's law states that at:
Medium
View SolutionIf $X$ is the specific resistance (resistivity) of the solution and $M$ is the molarity of the solution,the molar conductivity of the solution is given by:
Difficult
View SolutionConductivity of a solution is directly proportional to
Easy
View SolutionThe distance between electrodes of a conductivity cell is $0.98 \ cm$ and area of cross section is $1.96 \ cm^{2}$. What is the cell constant (in $cm^{-1}$)?
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo