At $298 \ K$,the resistance of a $0.01 \ N$ electrolyte solution is $210 \ \Omega$. If the cell constant of the conductivity cell used is $0.66 \ cm^{-1}$,what is the equivalent conductivity of the solution in $mho \ cm^2 \ eq^{-1}$?

What is the molar conductivity of $0.1 \ M$ $NaCl$ if its conductivity is $1.06 \times 10^{-2} \ \Omega^{-1} \ cm^{-1}$?

The conductivity of $0.20 \ M \ KCl$ solution at $300 \ K$ is $0.0248 \ \Omega^{-1} \ cm^{-1}$. What is its molar conductivity?

If the specific conductivity of $0.1 \, N$ nitric acid is $6.2 \times 10^{-2} \, \Omega^{-1} \, cm^{-1}$,what will be the molar conductivity of the solution in $\Omega^{-1} \, cm^{2} \, mol^{-1}$?

The resistance of a conductivity cell with cell constant $1.14 \, cm^{-1}$,containing $0.001 \, M \, KCl$ at $298 \, K$ is $1500 \, \Omega$. The molar conductivity of $0.001 \, M \, KCl$ solution at $298 \, K$ in $S \, cm^{2} \, mol^{-1}$ is ...... . (Integer answer)

The resistance of $0.01 \ M$ $KCl$ solution at $298 \ K$ is $1500 \ \Omega$. If the conductivity of $0.01 \ M$ $KCl$ solution at $298 \ K$ is $0.1466 \times 10^{-3} \ S \ cm^{-1}$,the cell constant of the conductivity cell in $cm^{-1}$ is: