The molar conductivities at infinite dilution for $AgNO_3$,$AgCl$,and $NaCl$ are $116.5$,$121.6$,and $110.3 \ S \ cm^2 \ mol^{-1}$ respectively. The molar conductivity of $NaNO_3$ is...

$\Lambda_m^0(NH_4OH)$ is equal to:

$A$ $KCl$ solution of conductivity $0.14 \, S m^{-1}$ shows a resistance of $4.19 \, \Omega$ in a conductivity cell. If the same cell is filled with an $HCl$ solution,the resistance drops to $1.03 \, \Omega$. The conductivity of the $HCl$ solution is $....... \, \times 10^{-2} \, S m^{-1}$. (Round off to the Nearest Integer).

At $298 \text{ K}$, the molar conductivity of $x\% \text{ (w/w)}$ $MX$ solution (aqueous) is $123.5 \text{ S cm}^2 \text{ mol}^{-1}$. The conductance of the same solution is $1.9 \times 10^{-3} \text{ S}$. The value of $x$ is . . . . . . $\times 10^{-2}$. (Given: cell constant = $1.3 \text{ cm}^{-1}$; molar mass of $MX$ is $75 \text{ g mol}^{-1}$, density of aqueous solution of $MX$ at $298 \text{ K}$ is $1.0 \text{ g mL}^{-1}$)

The limiting molar conductivities of $X^{+}$ and $Y^{-2}$ ions are $45$ and $110 \ S \ cm^2 \ mol^{-1}$ respectively. The $\Lambda_{m}^{\infty}$ of $X_2Y$ is:

What is the $SI$ unit of conductivity?