According to Kohlrausch's law,what is the limiting molar conductivity of the electrolyte $A_2B$?

What is the conductivity of $0.05 \ M \ BaCl_2$ solution if its molar conductivity is $220 \ \Omega^{-1} \ cm^2 \ mol^{-1}$?

Find out the ionisation constant of a weak acid $(HA)$ in terms of $\Lambda_m^o$ and $\Lambda_m^c$. (Given $\alpha$ cannot be ignored with respect to $1$)

Resistance of $0.2 \, M$ solution of an electrolyte is $50 \, \Omega$. The specific conductance of the solution is $1.4 \, S \, m^{-1}$. The resistance of $0.5 \, M$ solution of the same electrolyte is $280 \, \Omega$. The molar conductivity of $0.5 \, M$ solution of the electrolyte in $S \, m^2 \, mol^{-1}$ is:

At $298 \text{ K}$, the molar conductivity of $x\% \text{ (w/w)}$ $MX$ solution (aqueous) is $123.5 \text{ S cm}^2 \text{ mol}^{-1}$. The conductance of the same solution is $1.9 \times 10^{-3} \text{ S}$. The value of $x$ is . . . . . . $\times 10^{-2}$. (Given: cell constant = $1.3 \text{ cm}^{-1}$; molar mass of $MX$ is $75 \text{ g mol}^{-1}$, density of aqueous solution of $MX$ at $298 \text{ K}$ is $1.0 \text{ g mL}^{-1}$)

The conductivity of a strong electrolyte is: