If a current of 0.4 A is passed through acid | vedclass

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(A) The reaction for the production of hydrogen is: $2H^+ + 2e^- \rightarrow H_2(g)$.According to Faraday's law,the number of moles of electrons passe

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$0.0836$

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(A) The reaction for the production of hydrogen is: $2H^+ + 2e^- ightarrow H_2(g)$.According to Faraday's law,the number of moles of electrons passed is $n = \frac{I 	imes t}{F} = \frac{0.4 \ A 	imes (30 	imes 60 \ s)}{96500 \ C/mol} \approx 0.00746 \ mol$.Since $2 \ moles$ of electrons produce $1 \ mole$ of $H_2$,the moles of $H_2$ produced is $n_{H_2} = \frac{0.00746}{2} = 0.00373 \ mol$.At $STP$,the volume of $1 \ mole$ of gas is $22.4 \ L$.Therefore,the volume of $H_2 = 0.00373 \ mol 	imes 22.4 \ L/mol \approx 0.0836 \ L$.

If a current of $0.4 \ A$ is passed through acidic water for $30 \ minutes$,calculate the volume of hydrogen gas produced at $STP$ in liters.

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