The electrochemical cell is set up as follows: $Pt (H_2, 1 \, atm) | HCl (0.1 \, M) || \text{Acetic Acid} (0.1 \, M) | (H_2, 1 \, atm) Pt$. The $E.M.F.$ of the cell is not zero because:
- AThe $pH$ of $0.1 \, M \, HCl$ and $0.1 \, M$ acetic acid are not equal.
- BThe acids are used in two different containers.
- CThe $E.M.F.$ of the cell depends on the molarity of the acids used.
- DAt constant temperature.
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Similar Questions
Which of the following formulae is used to obtain the value of $E_{\text{cell}}^{\circ}$ for a reaction taking place in a Dry cell?
Which one of the following reactions does not take place?
The zinc/silver oxide cell is used in electric watches. The reaction is as follows:
$Zn(s) + Ag_2O(s) + H_2O(l) \rightarrow Zn^{2+}(aq) + 2Ag(s) + 2OH^-(aq)$
Given:
$Zn^{2+} + 2e^- \rightarrow Zn ; E^{\circ} = -0.760 \, V$
$Ag_2O + H_2O + 2e^- \rightarrow 2Ag + 2OH^- ; E^{\circ} = 0.344 \, V$
If $F = 96,500 \, C \, mol^{-1}$,the $\Delta G^{\circ}$ of the cell will be $....$ (in $kJ \, mol^{-1}$)
$Zn(s) + Ag_2O(s) + H_2O(l) \rightarrow Zn^{2+}(aq) + 2Ag(s) + 2OH^-(aq)$
Given:
$Zn^{2+} + 2e^- \rightarrow Zn ; E^{\circ} = -0.760 \, V$
$Ag_2O + H_2O + 2e^- \rightarrow 2Ag + 2OH^- ; E^{\circ} = 0.344 \, V$
If $F = 96,500 \, C \, mol^{-1}$,the $\Delta G^{\circ}$ of the cell will be $....$ (in $kJ \, mol^{-1}$)
Limiting molar conductivity of $Mg^{2+}$ and $Cl^{-}$ ions in water is $106.0 \ S \ cm^2 \ mol^{-1}$ and $76.3 \ S \ cm^2 \ mol^{-1}$ respectively. The limiting molar conductivity of magnesium chloride (in $S \ cm^2 \ mol^{-1}$) in water is
Assertion : For the Daniel cell,$Zn|Zn^{2+} || Cu^{2+}|Cu$ with $E_{cell} = 1.1 \ V$,the application of an opposite potential greater than $1.1 \ V$ results in the flow of electrons from cathode to anode.
Reason : $Zn$ is deposited at the anode,and $Cu$ is deposited at the cathode.
Reason : $Zn$ is deposited at the anode,and $Cu$ is deposited at the cathode.
DifficultAIIMS 2006
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