The bond angle in PH_3 is closest to which of | vedclass

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(A) In the corresponding compound $NH_3$,the bond angle is $107^o$.However,in $PH_3$,the bond angle is approximately $90^o$.This is because,despite ha

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$90$

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(A) In the corresponding compound $NH_3$,the bond angle is $107^o$.However,in $PH_3$,the bond angle is approximately $90^o$.This is because,despite having a similar electronic structure,the electronegativity of the central atom $(P)$ is lower than that of $N$. As a result,the bonding electrons are further from the central atom,reducing the $bp-bp$ repulsion and causing the bond angle to decrease towards $90^o$.

List-$I$ Molecule/ion	List-$II$ Bond pair : lone pair (on the central atom)
$A. ICl_2^-$	$I. 4 : 2$
$B. H_2O$	$II. 4 : 1$
$C. SO_2$	$III. 2 : 3$
$D. XeF_4$	$IV. 2 : 2$

The bond angle in $PH_3$ is closest to which of the following $^o$?

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Match the List-$I$ with List-$II$.

List-$I$ Molecule/ion List-$II$ Bond pair : lone pair (on the central atom)

$A. ICl_2^-$ $I. 4 : 2$

$B. H_2O$ $II. 4 : 1$

$C. SO_2$ $III. 2 : 3$

$D. XeF_4$ $IV. 2 : 2$

Choose the correct answer from the options given below:

Which of the following shapes cannot be obtained from trigonal bipyramidal geometry?

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