What are the hybridization states of carbon in diamond,graphite,and acetylene,respectively?

  • A
    $sp^2, sp, sp^3$
  • B
    $sp, sp^2, sp^3$
  • C
    $sp^3, sp^2, sp$
  • D
    $sp^2, sp^3, sp$

Explore More

Similar Questions

Which statement is correct about $CO_2$ if the central atom uses $s + P_x$ orbitals in hybridization?
$(i)$ $\pi$ bond will be formed by $P_y$ and $P_z$
$(ii)$ molecule can be in $XY$ plane
$(iii)$ molecule can be in $XZ$ plane
$(iv)$ molecule can be in infinite plane
$(v)$ molecule can be in $YZ$ plane
Correct code is:

Difficult
View Solution

In which of the following pairs do both the species have $sp^{3}$ hybridization?

If the dipole moment of an $MX_3$ molecule is zero,which orbital is used by the $M$ atom to form sigma bonds? (Atomic number of $M < 21$)

$CCl_4$ has the hybridization:

Sulphur trioxide is dissolved in heavy water to form a compound $X$. The hybridisation state of sulphur in $X$ is :

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo