BCl_3 molecule is planar while NCl_3 is pyram | vedclass

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Question

(A) According to $VSEPR$ theory,the shape of a molecule depends on the number of bonding and non-bonding electron pairs around the central atom.In $BC

Vedclass · Accepted Answer

$B$ in $BCl_3$ has no lone pair of electrons,whereas $N$ in $NCl_3$ has one lone pair.

Vedclass · Answer

(A) According to $VSEPR$ theory,the shape of a molecule depends on the number of bonding and non-bonding electron pairs around the central atom.In $BCl_3$,the central $B$ atom has $3$ bonding pairs and $0$ lone pairs,resulting in $sp^2$ hybridization and a trigonal planar geometry.In $NCl_3$,the central $N$ atom has $3$ bonding pairs and $1$ lone pair,resulting in $sp^3$ hybridization and a pyramidal geometry due to the lone pair-bond pair repulsion.

$A$	$B$
$CH_3OH$	$CH_3OCH_3$

List-$I$ (molecules/ions)	List-$II$ (No. of lone pairs of $e^-$ on central atom)
$A$. $IF_7$	$I$. Three
$B$. $ICl_4^-$	$II$. One
$C$. $XeF_6$	$III$. Two
$D$. $XeF_2$	$IV$. Zero

$BCl_3$ molecule is planar while $NCl_3$ is pyramidal because...

Similar Questions

Which of the following pairs has the same structure?

Which of the following species has a pyramidal shape?

Bond angle is minimum for

The bond angle in $A$ is $X$ and the bond angle in $B$ is $Y$. What are $X$ and $Y$?
$A$ $B$
$CH_3OH$ $CH_3OCH_3$

Match List-$I$ with List-$II$.

List-$I$ (molecules/ions) List-$II$ (No. of lone pairs of $e^-$ on central atom)

$A$. $IF_7$ $I$. Three

$B$. $ICl_4^-$ $II$. One

$C$. $XeF_6$ $III$. Two

$D$. $XeF_2$ $IV$. Zero

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