What is the bond angle around an atom that undergoes $sp^2$ hybridization?
- A$120^o$
- B$180^o$
- C$105^o$
- D$109^o 28'$
Explore More
Similar Questions
Identify the correct match:
Column $I$ (Molecule/ion) Column $II$ (Hybridisation) $A$. $H_3O^{+}$ $P$. $sp$ $B$. $NH_2^{-}$ $Q$. $sp^2$ $C$. $NO_3^{-}$ $R$. $sp^3$ $D$. $ClF_3$ $S$. $sp^3d$
| Column $I$ (Molecule/ion) | Column $II$ (Hybridisation) |
| $A$. $H_3O^{+}$ | $P$. $sp$ |
| $B$. $NH_2^{-}$ | $Q$. $sp^2$ |
| $C$. $NO_3^{-}$ | $R$. $sp^3$ |
| $D$. $ClF_3$ | $S$. $sp^3d$ |
Medium
View SolutionMatch the following:
List-$I$ List-$II$ $(a)$ $SF_6$ $(i)$ $sp^3d^2$ $(b)$ $PCl_5$ (ii) $sp^3d$ $(c)$ $XeF_4$ (iii) $sp^3d^3$ $(d)$ $IF_7$ (iv) $sp^3d^2$
The correct answer is:
| List-$I$ | List-$II$ |
| $(a)$ $SF_6$ | $(i)$ $sp^3d^2$ |
| $(b)$ $PCl_5$ | (ii) $sp^3d$ |
| $(c)$ $XeF_4$ | (iii) $sp^3d^3$ |
| $(d)$ $IF_7$ | (iv) $sp^3d^2$ |
The correct answer is:
The trigonal bipyramidal geometry results from the hybridization:
Medium
View SolutionWhich of the following molecular geometries is not produced by $sp^3$ hybridisation?
Medium
View SolutionIn $CCl_4$,the four valencies of carbon are directed towards the four corners of which of the following?
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo