What is the type of hybridization of Xe in Xe | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The total number of valence electrons in $XeF_2$ is $8 + (2 	imes 7) = 22$. To find the hybridization,we calculate the steric number $(X)$: $X =

Vedclass · Accepted Answer

$sp^3d$

Vedclass · Answer

(C) The total number of valence electrons in $XeF_2$ is $8 + (2 	imes 7) = 22$. To find the hybridization,we calculate the steric number $(X)$: $X = \frac{1}{2} [V + M - C + A]$,where $V$ is the number of valence electrons of the central atom,$M$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge. For $XeF_2$: $V = 8$,$M = 2$,$C = 0$,$A = 0$. $X = \frac{1}{2} [8 + 2] = 5$. $A$ steric number of $5$ corresponds to $sp^3d$ hybridization.

What is the type of hybridization of $Xe$ in $XeF_2$?

Similar Questions

Which one of the following is a correct set?

The maximum number of $90^{\circ}$ angles between bond pair-bond pair of electrons is observed in

What is the hybridization state of the central atom in the conjugate base of $NH_4^{+}$ ion?

In $CCl_4$,the four valencies of carbon are directed towards the four corners of which of the following?

The correct geometry and hybridization for $XeF_4$ are

Vedclass Test Series

Exam Paper Generator

Online Exam Module