What is the bond order of O_2^- (in .5)? | vedclass

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(A) The total number of electrons in $O_2^-$ is $8 + 8 + 1 = 17$. According to Molecular Orbital Theory,the electronic configuration is: $KK \sigma 2s

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(A) The total number of electrons in $O_2^-$ is $8 + 8 + 1 = 17$. According to Molecular Orbital Theory,the electronic configuration is: $KK \sigma 2s^2 \sigma^* 2s^2 \sigma 2p_z^2 \pi 2p_x^2 = \pi 2p_y^2 \pi^* 2p_x^2 = \pi^* 2p_y^1$. Number of bonding electrons $(N_b)$ = $8$. Number of antibonding electrons $(N_a)$ = $7$. Bond Order $(B.O.)$ = $\frac{1}{2}(N_b - N_a) = \frac{8 - 7}{2} = 0.5$.

What is the bond order of $O_2^-$ (in $.5$)?

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