In the reaction sequence $CH_3CH_2Br$ $\xrightarrow{AgCN} A$ $\xrightarrow{H_3O^+} HCOOH + B; B$ $\xrightarrow{CHCl_3/KOH} A$ $\xrightarrow{Reduction} C$,what are $A, B,$ and $C$ respectively?

  • A
    Ethyl isocyanide,Ethylamine,and $N$-methylethanamine
  • B
    Ethyl isocyanide,Ethylamine,and $N$-ethylethanamine
  • C
    Ethyl cyanide,Ethylamine,and $N$-methylethanamine
  • D
    Ethyl isocyanide,Methylamine,and $N$-methylethanamine

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In the given reaction,identify the final product.

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Three isomers $A$,$B$,and $C$ (molecular formula $C_8H_{11}N$) give the following results:
$A$ and $C$ $\xrightarrow{\text{Diazotization}}$ $P + Q$ $\xrightarrow[(ii) \text{ oxidation } (KMnO_4 + H^{+})]{(i) \text{ Hydrolysis}}$ $R$ (product of $A$) and $S$ (product of $C$)
Identify $A$,$B$,and $C$ from the given options.

$STATEMENT-1$: Aniline on reaction with $NaNO_2 / HCl$ at $0^{\circ} C$ followed by coupling with $\beta$-naphthol gives a dark blue coloured precipitate.
$STATEMENT-2$: The colour of the compound formed in the reaction of aniline with $NaNO_2 / HCl$ at $0^{\circ} C$ followed by coupling with $\beta$-naphthol is due to the extended conjugation.

Which of the following reactions does $NOT$ yield an amine?

The following transformation can be accomplished by:

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