(A) The reaction of an amide $(CH_3CONH_2)$ with sodium and alcohol $(Na/ROH)$ is a reduction reaction.$CH_3CONH_2 + 4[H] \xrightarrow{Na/ROH} CH_3CH_

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(A) The reaction of an amide $(CH_3CONH_2)$ with sodium and alcohol $(Na/ROH)$ is a reduction reaction.$CH_3CONH_2 + 4[H] \xrightarrow{Na/ROH} CH_3CH_2NH_2 + H_2O$.Here,the amide is reduced to the corresponding primary amine,which is $CH_3CH_2NH_2$ (ethanamine).