An aromatic compound A reacts with Zn/NH_4Cl, | vedclass

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Question

(B) The reaction of an aromatic nitro compound $(Ar-NO_2)$ with $Zn/NH_4Cl$ (a mild reducing agent) produces an aromatic hydroxylamine $(Ar-NHOH)$.$Ar

Vedclass · Accepted Answer

$-NO_2$

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(B) The reaction of an aromatic nitro compound $(Ar-NO_2)$ with $Zn/NH_4Cl$ (a mild reducing agent) produces an aromatic hydroxylamine $(Ar-NHOH)$.$Ar-NO_2 + Zn/NH_4Cl \rightarrow Ar-NHOH + ZnO$$Ar-NHOH$ is a strong reducing agent that reduces Tollens' reagent (ammoniacal silver nitrate) to metallic silver $(Ag)$,which appears as a black precipitate.Therefore,the compound $A$ must contain a $-NO_2$ group.

An aromatic compound $A$ reacts with $Zn/NH_4Cl$,and the filtrate is then added to an ammoniacal silver nitrate solution,resulting in a black precipitate. Which group does compound $A$ contain?

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