What is the product formed by the reaction be | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $N$-bromosuccinimide $(NBS)$ is a reagent used for free radical bromination at the benzylic position. In ethylbenzene $(C_6H_5CH_2CH_3)$,the benzy

Vedclass · Accepted Answer

$1-$bromo$-1-$phenylethane

Vedclass · Answer

(C) $N$-bromosuccinimide $(NBS)$ is a reagent used for free radical bromination at the benzylic position. In ethylbenzene $(C_6H_5CH_2CH_3)$,the benzylic carbon is the carbon atom directly attached to the benzene ring. The reaction proceeds via a free radical mechanism to replace a hydrogen atom on the benzylic carbon with a bromine atom. Thus,the reaction of ethylbenzene with $NBS$ yields $1-$bromo$-1-$phenylethane $(C_6H_5CH(Br)CH_3)$.

What is the product formed by the reaction between ethylbenzene and $N$-bromosuccinimide $(NBS)$?

Similar Questions

Arrange the following three chlorides in decreasing order of their reactivity towards $S_{N^1}$ reaction.

Identify compound $Y$ in the following reaction.
$C_2H_5Cl + Y \xrightarrow{\Delta} C_2H_5CN$

In which of the following reactions is an anti-Markovnikov product formed?

Arrange the following compounds in decreasing order of reactivity for nucleophilic substitution reaction:
$(I)$ $CH_3-CH_2-OSO_2CF_3$
$(II)$ $CH_3-CH_2-OTs$
$(III)$ $CH_3-CH(OH)-CH_3$
$(IV)$ $C_6H_5-CH(OH)-CH_3$

For the reaction:
$RCH_2Br + I^{-} \stackrel{\text{Acetone}}{\longrightarrow} RCH_2I + Br^{-}$
The correct statement is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module