Which of the following pairs of ions are both | vedclass

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(B) An ion is colored if it has unpaired electrons in its $d$-orbitals ($d-d$ transition).$1$. $Sc^{3+}$ $([Ar] 3d^0)$: No unpaired electrons,colorles

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$Ni^{2+}, Ti^{3+}$

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(B) An ion is colored if it has unpaired electrons in its $d$-orbitals ($d-d$ transition).$1$. $Sc^{3+}$ $([Ar] 3d^0)$: No unpaired electrons,colorless.$2$. $Ti^{3+}$ $([Ar] 3d^1)$: One unpaired electron,colored.$3$. $Ni^{2+}$ $([Ar] 3d^8)$: Two unpaired electrons,colored.$4$. $Co^{3+}$ $([Ar] 3d^6)$: Four unpaired electrons,colored.$5$. $Lu^{+}$ is not a standard transition metal ion in this context; assuming the question implies $Cu^{+}$ $([Ar] 3d^{10})$,it is colorless.Comparing the options,$Ni^{2+}$ and $Ti^{3+}$ both have unpaired electrons and are colored in aqueous solution.

Which of the following pairs of ions are both colored in aqueous solution? (Atomic numbers: $Sc = 21, Ti = 22, Co = 27, Ni = 28, Cu = 29$)

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The correct option among the following is:

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