Which of the following lanthanoid elements ex | vedclass

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Question

(D) The lanthanoids typically exhibit a $+3$ oxidation state. However,some elements show $+2$ or $+4$ oxidation states due to stable electronic config

Vedclass · Accepted Answer

$Eu$

Vedclass · Answer

(D) The lanthanoids typically exhibit a $+3$ oxidation state. However,some elements show $+2$ or $+4$ oxidation states due to stable electronic configurations (like half-filled or fully-filled $f$-orbitals). $Eu$ ($Europium$,atomic number $63$) has the electronic configuration $[Xe] 4f^7 6s^2$. By losing two electrons from the $6s$ orbital,it forms the $Eu^{2+}$ ion,which has a stable half-filled $4f^7$ configuration. Thus,$Eu$ commonly exhibits both $+2$ and $+3$ oxidation states.

Which of the following lanthanoid elements exhibits common oxidation states of $+2$ and $+3$?

Similar Questions

The $Eu^{2+}$ ion is a strong reducing agent in spite of its ground state electronic configuration (outermost) : [Atomic number of $Eu=63$]

The incorrect statement among the following is:

Which of the following hydroxides is the most basic?

Which of the following lanthanoids shows $+4$ oxidation state to acquire noble gas configuration?
(At nos. : $La=57, Ce=58, Eu=63$ and $Yb=70$ )

Which of the following compounds is the most acidic?

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