Which transition metal configuration exhibits | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The oxidation state of transition metals depends on the number of electrons available for bonding in the $(n-1)d$ and $ns$ orbitals. Transition me

Vedclass · Accepted Answer

$(n - 1)d^5 ns^2$

Vedclass · Answer

(C) The oxidation state of transition metals depends on the number of electrons available for bonding in the $(n-1)d$ and $ns$ orbitals. Transition metals with the configuration $(n-1)d^5 ns^2$ (such as $Mn$,$Z=25$) have the maximum number of unpaired electrons (seven in total),allowing them to exhibit the highest oxidation states (e.g.,$+7$ in $KMnO_4$). Therefore,the configuration $(n-1)d^5 ns^2$ corresponds to the highest oxidation state.

Which transition metal configuration exhibits the highest oxidation state?

Similar Questions

In the electronic configuration of which of the following elements is an electron arranged in the $5d$ orbital?

Which element from the following exhibits the highest number of various different possible oxidation states?

Which of the following paramagnetic ions has a magnetic moment (spin-only) of the order of $5 \ BM$? $(Mn = 25, Cr = 24, V = 23, Ti = 22)$

What is the total number of transition series of $d$-block elements?

In which of the following ions is $d-d$ transition $NOT$ possible?

Vedclass Test Series

Exam Paper Generator

Online Exam Module