Arrange the following ions in the increasing | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The magnetic moment is calculated using the formula $\mu = \sqrt{n(n+2)} \, BM$,where $n$ is the number of unpaired electrons.$(i) \, V^{4+} (Z=23

Vedclass · Accepted Answer

$(iii) > (ii) > (iv) > (i)$

Vedclass · Answer

(C) The magnetic moment is calculated using the formula $\mu = \sqrt{n(n+2)} \, BM$,where $n$ is the number of unpaired electrons.$(i) \, V^{4+} (Z=23): [Ar] 3d^1$,$n=1$,$\mu = \sqrt{1(1+2)} = \sqrt{3} \approx 1.73 \, BM$.$(ii) \, Mn^{4+} (Z=25): [Ar] 3d^3$,$n=3$,$\mu = \sqrt{3(3+2)} = \sqrt{15} \approx 3.87 \, BM$.$(iii) \, Fe^{3+} (Z=26): [Ar] 3d^5$,$n=5$,$\mu = \sqrt{5(5+2)} = \sqrt{35} \approx 5.92 \, BM$.$(iv) \, Ni^{2+} (Z=28): [Ar] 3d^8$,$n=2$,$\mu = \sqrt{2(2+2)} = \sqrt{8} \approx 2.83 \, BM$.Comparing the values: $5.92 (Fe^{3+}) > 3.87 (Mn^{4+}) > 2.83 (Ni^{2+}) > 1.73 (V^{4+})$.Thus,the order is $(iii) > (ii) > (iv) > (i)$.

Arrange the following ions in the increasing order of their magnetic moments: $(i) \, V^{4+}$,$(ii) \, Mn^{4+}$,$(iii) \, Fe^{3+}$,$(iv) \, Ni^{2+}$. $[V = 23, Mn = 25, Fe = 26, Ni = 28]$

Similar Questions

The ionisation energies of transition elements are

The $E^{\circ}$ value for the $Mn^{3+} / Mn^{2+}$ couple is more positive than that of $Cr^{3+} / Cr^{2+}$ or $Fe^{3+} / Fe^{2+}$ due to change of

Which compound has a coloured aqueous solution?

The colour of an electrolyte solution depends on

Which among the following properties is $\underline{NOT}$ exhibited by transition elements?

Vedclass Test Series

Exam Paper Generator

Online Exam Module