(C) The electronic configuration of the $M^{2+}$ ion is $[Ar] \, 3d^8$.This means the ion has lost $2$ electrons from its neutral state.The neutral at

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(C) The electronic configuration of the $M^{2+}$ ion is $[Ar] \, 3d^8$.This means the ion has lost $2$ electrons from its neutral state.The neutral atom $M$ would have the configuration $[Ar] \, 3d^8 \, 4s^2$.Adding the electrons: $18$ (from Argon) $+ 8 + 2 = 28$.Therefore,the atomic number of the element is $28$.

Class 11 Chemistry Structure of Atom Quantum number, Electronic configuration and Shape of orbitals

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What is the atomic number of an element whose $M^{2+}$ ion has the electronic configuration $[Ar] \, 3d^8$?

A
$26$
B
$27$
C
$28$
D
$25$

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Quantum number, Electronic configuration and Shape of orbitals

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What is the atomic number of an element whose $M^{2+}$ ion has the electronic configuration $[Ar] \, 3d^8$?

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