The valence shell electronic configuration is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given the configuration: $(n - 1)s^2 (n - 1)p^6 (n - 1)d^x ns^2$.Substituting $n = 4$ and $x = 5$,we get the configuration of the valence and inne

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(C) Given the configuration: $(n - 1)s^2 (n - 1)p^6 (n - 1)d^x ns^2$.Substituting $n = 4$ and $x = 5$,we get the configuration of the valence and inner shells as $3s^2 3p^6 3d^5 4s^2$.The total number of electrons is the sum of electrons in all shells: $1s^2 2s^2 2p^6 3s^2 3p^6 3d^5 4s^2$.Total electrons $= 2 + 2 + 6 + 2 + 6 + 5 + 2 = 25$.Since the atom is neutral,the number of protons equals the number of electrons,which is $25$.

The valence shell electronic configuration is $(n - 1)s^2 (n - 1)p^6 (n - 1)d^x ns^2$. If $n = 4$ and $x = 5$,what is the number of protons in the element?

Similar Questions

Following Hund's rule,which element contains six unpaired electrons?

The number of atomic orbitals from the following having $5$ radial nodes is $.......$. $7s, 7p, 6s, 8p, 8d$

Which of the following statements is not correct about the electronic configuration of a gaseous chromium $(Cr)$ atom?

Which of the following orbitals is non-directional?

The number of radial and angular nodes in $4d$ orbital are,respectively $........$ .

Vedclass Test Series

Exam Paper Generator

Online Exam Module