Which of the following compounds of Ti (Z = 2 | vedclass

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(D) The common oxidation states of $Ti$ are $+2, +3$,and $+4$. In the compound $K_2TiO_4$,the oxidation state of $Ti$ is calculated as: $2(+1) + x + 4

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$K_2TiO_4$

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(D) The common oxidation states of $Ti$ are $+2, +3$,and $+4$. In the compound $K_2TiO_4$,the oxidation state of $Ti$ is calculated as: $2(+1) + x + 4(-2) = 0$,which gives $x = +6$. Since $Ti$ $(Z = 22)$ has the electronic configuration $[Ar] 3d^2 4s^2$,it can lose a maximum of $4$ electrons. Therefore,an oxidation state of $+6$ is not possible for $Ti$,and $K_2TiO_4$ does not exist.

Which of the following compounds of $Ti$ $(Z = 22)$ does not exist?

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