(i) La(OH)_3 is the least basic among lanthan | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Statement $(i)$ is incorrect because $La(OH)_3$ is the most basic lanthanide hydroxide due to the largest ionic radius of $La^{3+}$. As we move fr

Vedclass · Accepted Answer

$(ii)$ and $(iii)$

Vedclass · Answer

(B) Statement $(i)$ is incorrect because $La(OH)_3$ is the most basic lanthanide hydroxide due to the largest ionic radius of $La^{3+}$. As we move from $La$ to $Lu$,the ionic radius decreases,leading to a decrease in basicity.Statement $(ii)$ is correct because $Zr^{4+}$ and $Hf^{4+}$ have almost identical ionic radii due to lanthanoid contraction.Statement $(iii)$ is correct because $Ce^{4+}$ has a strong tendency to gain an electron to form the stable $Ce^{3+}$ $(4f^1)$ configuration,thus acting as a strong oxidizing agent.Therefore,statements $(ii)$ and $(iii)$ are correct.

$(i) La(OH)_3$ is the least basic among lanthanide hydroxides. $(ii) Zr^{4+}$ and $Hf^{4+}$ have almost identical ionic radii. $(iii) Ce^{4+}$ can act as an oxidizing agent. Which of the above statements are correct?

Similar Questions

Identify the non-radioactive element from the following.

Which of the following acts as a strong reducing agent? (Atomic number: $Ce=58, Eu=63, Gd=64, Lu=71$)

Compare the chemistry of actinoids with that of the lanthanoids with special reference to:
$(i)$ electronic configuration
$(ii)$ atomic and ionic sizes
$(iii)$ oxidation state
$(iv)$ chemical reactivity.

The pair of lanthanoid ions which are diamagnetic is

Amongst the given elements,which one exhibits a $+4$ oxidation state in an aqueous medium?

Vedclass Test Series

Exam Paper Generator

Online Exam Module