Which of the following electronic configurati | vedclass

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(B) The maximum oxidation state of a transition element is determined by the total number of electrons in the $(n-1)d$ and $ns$ orbitals.For option $A

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$(n - 1)d^8 ns^2$

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(B) The maximum oxidation state of a transition element is determined by the total number of electrons in the $(n-1)d$ and $ns$ orbitals.For option $A$: $(n-1)d^5 ns^2$,total electrons = $5 + 2 = 7$.For option $B$: $(n-1)d^8 ns^2$,total electrons = $8 + 2 = 10$.For option $C$: $(n-1)d^5 ns^1$,total electrons = $5 + 1 = 6$.For option $D$: $(n-1)d^3 ns^2$,total electrons = $3 + 2 = 5$.Since the configuration in option $B$ has the highest number of valence electrons available for bonding,it can exhibit the highest oxidation state.

Which of the following electronic configurations represents an atom that can exhibit the highest oxidation state?

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