The ionic radius of La^{3+} is 1.06 mathop{A | vedclass

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(D) Due to the $Lanthanoid \ contraction$,the atomic and ionic radii of lanthanoids decrease regularly from $La^{3+}$ to $Lu^{3+}$.As the atomic numbe

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$0.85$

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(D) Due to the $Lanthanoid \ contraction$,the atomic and ionic radii of lanthanoids decrease regularly from $La^{3+}$ to $Lu^{3+}$.As the atomic number increases from $57$ to $71$,the effective nuclear charge increases,which pulls the electrons closer to the nucleus.Therefore,the ionic radius of $Lu^{3+}$ must be smaller than that of $La^{3+}$ $(1.06 \ \mathop{A}\limits^o)$.Among the given options,$0.85 \ \mathop{A}\limits^o$ is the closest and most reasonable value.

The ionic radius of $La^{3+}$ is $1.06 \ \mathop{A}\limits^o$. Which of the following is the closest value for the ionic radius of $Lu^{3+}$ in $\mathop{A}\limits^o$? $(Lu = 71, La = 57)$

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