A compound (a),C_8H_9Br,gives a white precipi | vedclass

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(D) $1$. The compound $(a)$ has the molecular formula $C_8H_9Br$. Since it gives a white precipitate with alcoholic $AgNO_3$,it must contain a reactiv

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$1-$bromo$-2-$methylbenzene

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(D) $1$. The compound $(a)$ has the molecular formula $C_8H_9Br$. Since it gives a white precipitate with alcoholic $AgNO_3$,it must contain a reactive halogen atom,likely a benzylic bromide.$2$. Oxidation of $(a)$ yields an acid $(b)$ with the formula $C_8H_6O_4$. This acid is phthalic acid (benzene$-1,2-$dicarboxylic acid) because it easily forms an anhydride upon heating.$3$. For the oxidation of $(a)$ to yield phthalic acid,the substituents on the benzene ring must be in the ortho position. Thus,$(a)$ must be $o$-methylbenzyl bromide ($1$-bromo$-2-$methylbenzene).$4$. The structure corresponds to option $(D)$.

$A$ compound $(a)$,$C_8H_9Br$,gives a white precipitate when heated with alcoholic $AgNO_3$. Oxidation of $(a)$ gives an acid $(b)$. The acid $(b)$,$C_8H_6O_4$,easily forms an anhydride on heating. Identify the compound $(a)$.

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