The hydrolysis of 2-bromo-3-methylbutane by t | vedclass

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(B) The hydrolysis of $2$-bromo-$3$-methylbutane via the $S_N1$ mechanism proceeds through the formation of a carbocation intermediate.$1$. The starti

Vedclass · Accepted Answer

$2$-methylbutan-$2$-ol

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(B) The hydrolysis of $2$-bromo-$3$-methylbutane via the $S_N1$ mechanism proceeds through the formation of a carbocation intermediate.$1$. The starting material is $(CH_3)_2CH-CH(Br)-CH_3$.$2$. Upon loss of the bromide ion,a secondary carbocation $(CH_3)_2CH-CH^+-CH_3$ is formed.$3$. This secondary carbocation undergoes a $1,2$-hydride shift to form a more stable tertiary carbocation: $(CH_3)_2C^+-CH_2-CH_3$.$4$. The nucleophile $(OH^-)$ then attacks the tertiary carbocation to form the major product,$2$-methylbutan-$2$-ol.

The hydrolysis of $2$-bromo-$3$-methylbutane by the $S_N1$ mechanism primarily yields:

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