In the reaction C_6H_5NH_2 + CHCl_3 + 3KOH ri | vedclass

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(B) The given reaction is the Carbylamine reaction,which is a characteristic test for primary amines.When a primary amine (aliphatic or aromatic) is h

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$C_6H_5NC$

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(B) The given reaction is the Carbylamine reaction,which is a characteristic test for primary amines.When a primary amine (aliphatic or aromatic) is heated with chloroform $(CHCl_3)$ and an alcoholic base (like $KOH$),it forms an isocyanide (also known as carbylamine),which has a foul smell.The balanced chemical equation is:$C_6H_5NH_2 + CHCl_3 + 3KOH \rightarrow C_6H_5NC + 3KCl + 3H_2O$Here,$C_6H_5NC$ (phenyl isocyanide) is the product '$A$'.

Column-$I$	Column-$II$
$(A)$ $ArN_2^{+} Cl^{-} \rightarrow ArOH$	$(p)$ $HBF_4 / NaNO_2, \Delta$
$(B)$ $ArN_2^{+} Cl^{-} \rightarrow ArNO_2$	$(q)$ $H_2 O$
$(C)$ $ArN_2^{+} Cl^{-} \rightarrow ArH$	$(r)$ $HBF_4, \Delta$
$(D)$ $ArN_2^{+} Cl^{-} \rightarrow ArF$	$(s)$ $CH_3CH_2OH$

In the reaction $C_6H_5NH_2 + CHCl_3 + 3KOH \rightarrow A + 3KCl + 3H_2O$,what is '$A$'?

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