What is the number of possible enantiomeric p | vedclass

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(A) Isopentane is $2$-methylbutane,which has the structure $CH_3-CH(CH_3)-CH_2-CH_3$. Monochlorination can occur at four different types of hydrogen a

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$2$

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(A) Isopentane is $2$-methylbutane,which has the structure $CH_3-CH(CH_3)-CH_2-CH_3$. Monochlorination can occur at four different types of hydrogen atoms: $1$. At $C_1$ (terminal methyl): $CH_2Cl-CH(CH_3)-CH_2-CH_3$ (achiral). $2$. At $C_2$ (tertiary carbon): $CH_3-CCl(CH_3)-CH_2-CH_3$ (chiral,forms a pair of enantiomers). $3$. At $C_3$ (secondary carbon): $CH_3-CH(CH_3)-CHCl-CH_3$ (chiral,forms a pair of enantiomers). $4$. At $C_4$ (terminal methyl): $CH_3-CH(CH_3)-CH_2-CH_2Cl$ (achiral). Thus,there are $2$ chiral centers formed,each resulting in a pair of enantiomers. Therefore,the number of possible enantiomeric pairs is $2$.

What is the number of possible enantiomeric pairs formed during the monochlorination of isopentane?

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