In E2 elimination,many substances follow the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The $E2$ elimination reaction typically follows $Zaitsev's$ rule,which favors the formation of the most substituted alkene. However,the $Hofmann$

Vedclass · Accepted Answer

The double bond is formed towards the less substituted carbon

Vedclass · Answer

(D) The $E2$ elimination reaction typically follows $Zaitsev's$ rule,which favors the formation of the most substituted alkene. However,the $Hofmann$ rule is the opposite,where the major product is the least substituted alkene. This occurs due to steric hindrance or electronic factors that make the removal of a proton from the less substituted carbon more favorable. Therefore,the $Hofmann$ rule means the double bond is formed towards the less substituted carbon.

In $E2$ elimination,many substances follow the Hofmann rule,which means.....

Similar Questions

$CH_3-CH_2-Cl + NaI \xrightarrow{\text{Acetone}} CH_3-CH_2-I + NaCl$ The above reaction is known as $:-$

Which of the following reactions is used for the conversion of alkyl chloride to alkyl iodide?

$A$ dihalogen derivative $X$ of a three-carbon hydrocarbon reacts with alcoholic $KOH$ to give another hydrocarbon,which gives a red precipitate with ammoniacal $Cu_2Cl_2$. Reaction of $X$ with aqueous $KOH$ gives an aldehyde. The compound $X$ is .......

Predict the major product for the following reaction: $CH_3-CH(CH_3)-ONa + (CH_3)_3C-Cl \xrightarrow{\Delta} \text{Major product}$

Which of the following compounds reacts with $KCN$ to form a cyanide?

Vedclass Test Series

Exam Paper Generator

Online Exam Module