Which of the following undergoes S_{N^{1}} re | vedclass

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Question

(A) $S_{N^{1}}$ reactions proceed via the formation of a carbocation intermediate. The stability of the carbocation determines the rate of the reactio

Vedclass · Accepted Answer

$(CH_3)_3C-Cl + KOH \rightarrow$

Vedclass · Answer

(A) $S_{N^{1}}$ reactions proceed via the formation of a carbocation intermediate. The stability of the carbocation determines the rate of the reaction. Tertiary $(3^{\circ})$ carbocations are the most stable due to the inductive effect and hyperconjugation of the three alkyl groups. In the reaction of $(CH_3)_3C-Cl$ with $KOH$,the rate-determining step involves the formation of a stable tertiary carbocation,$(CH_3)_3C^{\oplus}$. Therefore,$(CH_3)_3C-Cl$ readily undergoes $S_{N^{1}}$ reaction.

Which of the following undergoes $S_{N^{1}}$ reaction?

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