What is the decreasing order of coagulating p | vedclass

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(B) Arsenious sulphide $(As_2S_3)$ sol is a negatively charged colloid. According to the Hardy-Schulze rule,the coagulating power of an electrolyte de

Vedclass · Accepted Answer

$Al^{3+} > Ba^{2+} > Na^{+}$

Vedclass · Answer

(B) Arsenious sulphide $(As_2S_3)$ sol is a negatively charged colloid. According to the Hardy-Schulze rule,the coagulating power of an electrolyte depends on the valency of the ion carrying a charge opposite to that of the colloidal particles. Since the sol is negative,it is coagulated by positive ions. The coagulating power increases with the increase in the magnitude of the charge on the cation. Therefore,the order is $Al^{3+} > Ba^{2+} > Na^{+}$.

What is the decreasing order of coagulating power of ions for an arsenious sulphide sol based on their charge?

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