Given A = text{Nylon-}6,6,B = text{Buna-}S,an | vedclass

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(B) The strength of intermolecular forces in polymers depends on their structure:$1$. $B = 	ext{Buna-}S$ is an elastomer,which has the weakest interm

Vedclass · Accepted Answer

$B < C < A$

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(B) The strength of intermolecular forces in polymers depends on their structure:$1$. $B = 	ext{Buna-}S$ is an elastomer,which has the weakest intermolecular forces (weak van der Waals forces).$2$. $C = 	ext{Polythene}$ is a thermoplastic,which has intermediate intermolecular forces (stronger van der Waals forces than elastomers).$3$. $A = 	ext{Nylon-}6,6$ is a fiber,which has the strongest intermolecular forces due to hydrogen bonding.Therefore,the increasing order of intermolecular forces is $B < C < A$.

Given $A = \text{Nylon-}6,6$,$B = \text{Buna-}S$,and $C = \text{Polythene}$. Arrange these polymers in the increasing order of their intermolecular forces (from weakest to strongest).

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