Consider the following reactions:(a) CH_3-CH= | vedclass

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(A) Reaction $(a)$ is an electrophilic addition of $HBr$ to an alkene,which follows the ionic mechanism (Markovnikov addition).Reaction $(b)$ is the a

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$b, c$

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(A) Reaction $(a)$ is an electrophilic addition of $HBr$ to an alkene,which follows the ionic mechanism (Markovnikov addition).Reaction $(b)$ is the addition of $HBr$ to an alkene in the presence of peroxide,known as the Kharasch effect or peroxide effect,which proceeds via a free radical mechanism.Reaction $(c)$ is the free radical substitution of methane with chlorine in the presence of ultraviolet light $(hv)$,which proceeds via a free radical mechanism.Therefore,reactions $(b)$ and $(c)$ proceed via a free radical mechanism.

Consider the following reactions:
$(a)$ $CH_3-CH=CH_2 + HBr \rightarrow CH_3-CH(Br)-CH_3$
$(b)$ $CH_3-CH=CH_2 + HBr \xrightarrow{Peroxide} CH_3-CH_2-CH_2Br$
$(c)$ $CH_4 + Cl_2 \xrightarrow{hv} CH_3Cl + HCl$
Which of these reactions proceed via a free radical mechanism?

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Consider the following reactions:$(a)$ $CH_3-CH=CH_2 + HBr \rightarrow CH_3-CH(Br)-CH_3$$(b)$ $CH_3-CH=CH_2 + HBr \xrightarrow{Peroxide} CH_3-CH_2-CH_2Br$$(c)$ $CH_4 + Cl_2 \xrightarrow{hv} CH_3Cl + HCl$Which of these reactions proceed via a free radical mechanism?