When nitrobenzene is reacted with $Br_2$ in the presence of $FeBr_3$,the major product formed is $m$-bromonitrobenzene. This is because:

  • A
    The electron density at the meta carbon is higher than at the ortho and para positions.
  • B
    The meta position is the most stable site for the initial attack of $Br^+$ to form the intermediate carbocation.
  • C
    The aromaticity is lost when $Br^+$ attacks the ortho,para,or meta positions.
  • D
    The ortho and para positions lose $H^+$ more easily than the meta position to regain aromaticity.

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