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(B) The reaction involves the abstraction of a hydrogen atom by a bromine radical $(Br^\bullet)$.The stability of the resulting alkyl radical determin

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$H_3C-CH(D)-C^\bullet(CH_3)-CH_3$

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(B) The reaction involves the abstraction of a hydrogen atom by a bromine radical $(Br^\bullet)$.The stability of the resulting alkyl radical determines the major product.The stability order of alkyl radicals is $3^\circ > 2^\circ > 1^\circ$.In the reactant $H_3C-CH(D)-CH(CH_3)-CH_3$,the hydrogen at the $C_2$ position (the carbon attached to the methyl group) is a tertiary hydrogen $(3^\circ)$.Removing this hydrogen creates a $3^\circ$ radical,which is the most stable.Thus,the major product '$X$' is $H_3C-CH(D)-C^\bullet(CH_3)-CH_3$.

Considering the following reaction,what is the structure of the major product '$X$'?
$H_3C-CH(D)-CH(CH_3)-CH_3 + Br^\bullet \to 'X' + HBr$

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Considering the following reaction,what is the structure of the major product '$X$'?$H_3C-CH(D)-CH(CH_3)-CH_3 + Br^\bullet \to 'X' + HBr$