2-Butene exhibits geometrical isomerism due t | vedclass

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Question

(A) Geometrical isomerism in alkenes like $2$-butene $(CH_3-CH=CH-CH_3)$ arises because the carbon-carbon double bond consists of a $\sigma$-bond and

Vedclass · Accepted Answer

Restricted rotation around the double bond

Vedclass · Answer

(A) Geometrical isomerism in alkenes like $2$-butene $(CH_3-CH=CH-CH_3)$ arises because the carbon-carbon double bond consists of a $\sigma$-bond and a $\pi$-bond. The presence of the $\pi$-bond prevents free rotation around the $C=C$ axis,resulting in restricted rotation. This restricted rotation allows for the existence of distinct spatial arrangements of atoms or groups attached to the double-bonded carbons,leading to $cis$ and $trans$ isomers.

$2$-Butene exhibits geometrical isomerism due to:

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