What is the product A in the given reaction?C | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction of an alkyne with $H^+ / Hg^{2+}$ is an acid-catalyzed hydration reaction,which follows Markovnikov's rule.For the alkyne $C_6H_5-C \

Vedclass · Accepted Answer

$C_6H_5-CO-CH_2-CH_3$

Vedclass · Answer

(C) The reaction of an alkyne with $H^+ / Hg^{2+}$ is an acid-catalyzed hydration reaction,which follows Markovnikov's rule.For the alkyne $C_6H_5-C \equiv C-CH_3$,the addition of water occurs across the triple bond.The $OH^-$ group attaches to the carbon atom that is more substituted or stabilized by the phenyl group,leading to the formation of an enol intermediate.Specifically,the intermediate is $C_6H_5-C(OH)=CH-CH_3$.This enol then undergoes tautomerization to form the more stable ketone,which is $C_6H_5-CO-CH_2-CH_3$ (propiophenone derivative).However,looking at the options provided,option $C$ represents the final ketone product.

What is the product $A$ in the given reaction?
$C_6H_5-C \equiv C-CH_3 \xrightarrow{H^+ / Hg^{2+}} A$

Similar Questions

The reagent which could distinguish between $1-$hexyne and $1-$hexene is

$CH_3-C \equiv C-O-CH_3 \xrightarrow{dil. \ H_2SO_4, HgSO_4} \text{major product}$

When $Mg_2C_3$ is reacted with water,a compound $X$ is formed which on heating with $Na$ followed by treatment with $C_2H_5Br$ gives another compound $Y$. Calculate the number of sigma bonds in $Y$.

$CH_3-CH_2-CH_2-C\equiv CH + LiNH_2 \to (A) \xrightarrow{(CH_3)_2SO_4} (B)$
Give the structural formula of compound $(B)$.

What is formed when acetylene reacts with hypochlorous acid?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

What is the product $A$ in the given reaction?$C_6H_5-C \equiv C-CH_3 \xrightarrow{H^+ / Hg^{2+}} A$