What is the product formed when CH_3CH_2CHCl_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction of a geminal dihalide like $CH_3CH_2CHCl_2$ with a strong base like $NaNH_2$ (sodamide) proceeds via dehydrohalogenation. First,one m

Vedclass · Accepted Answer

$CH_3-C\equiv CH$

Vedclass · Answer

(B) The reaction of a geminal dihalide like $CH_3CH_2CHCl_2$ with a strong base like $NaNH_2$ (sodamide) proceeds via dehydrohalogenation. First,one molecule of $HCl$ is eliminated to form a vinyl halide $(CH_3CH=CHCl)$. Then,the second molecule of $HCl$ is eliminated by the excess $NaNH_2$ to form an alkyne. Thus,$CH_3CH_2CHCl_2 \xrightarrow{NaNH_2} CH_3-C\equiv CH$.

What is the product formed when $CH_3CH_2CHCl_2$ is treated with $NaNH_2$?

Similar Questions

When $23 \ g$ of $Na$ reacts with $1 \ mole$ of propyne,how many moles of $H_2$ gas will be released?

How can propyne and propene be distinguished?

In the given reactions,identify $A$ and $B$.

Which of the following reagents is most suitable to distinguish compound $(3)$ from the others?
$(1) \ CH_3-C \equiv C-CH_3$
$(2) \ CH_3CH_2CH_2CH_3$
$(3) \ CH_3CH_2C \equiv CH$
$(4) \ CH_3CH=CH_2$

In which reaction is the final product $Ph-C \equiv CH$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module