The reaction of 1-chlorobutane with alcoholic | vedclass

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Question

(A) The reaction of $1$-chlorobutane $(CH_3CH_2CH_2CH_2Cl)$ with alcoholic $KOH$ (potash) is a dehydrohalogenation reaction.This is an elimination rea

Vedclass · Accepted Answer

$1$-butene

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(A) The reaction of $1$-chlorobutane $(CH_3CH_2CH_2CH_2Cl)$ with alcoholic $KOH$ (potash) is a dehydrohalogenation reaction.This is an elimination reaction ($E2$ mechanism) where the base $(OH^-)$ removes a hydrogen atom from the $\beta$-carbon,leading to the formation of an alkene.$CH_3CH_2CH_2CH_2Cl + KOH (	ext{alc.}) ightarrow CH_3CH_2CH=CH_2 + KCl + H_2O$.The product formed is $1$-butene.

The reaction of $1$-chlorobutane with alcoholic potash gives $......$.

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