2-Bromobutane is obtained by the reaction of: | vedclass

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Question

(A) The addition of $HBr$ to alkenes follows Markovnikov's rule.For the formation of $2$-bromobutane $(CH_3-CH(Br)-CH_2-CH_3)$,the starting material s

Vedclass · Accepted Answer

$CH_3-CH=CH-CH_3 + HBr$

Vedclass · Answer

(A) The addition of $HBr$ to alkenes follows Markovnikov's rule.For the formation of $2$-bromobutane $(CH_3-CH(Br)-CH_2-CH_3)$,the starting material should be but-$2$-ene $(CH_3-CH=CH-CH_3)$.When $CH_3-CH=CH-CH_3$ reacts with $HBr$,the proton $(H^+)$ adds to one of the $sp^2$ carbons and the bromide ion $(Br^-)$ adds to the other,resulting in $2$-bromobutane.Reaction: $CH_3-CH=CH-CH_3 + HBr \rightarrow CH_3-CH(Br)-CH_2-CH_3$.

$2$-Bromobutane is obtained by the reaction of:

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