The gas evolved by the reaction of ethyl iodi | vedclass

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Question

(C) The reaction of ethyl iodide $(C_2H_5I)$ with alcoholic $KOH$ undergoes a dehydrohalogenation reaction (elimination reaction) to form ethene $(C_2

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$C_2H_4$

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(C) The reaction of ethyl iodide $(C_2H_5I)$ with alcoholic $KOH$ undergoes a dehydrohalogenation reaction (elimination reaction) to form ethene $(C_2H_4)$.$C_2H_5I + KOH (	ext{alc.}) ightarrow C_2H_4 + KI + H_2O$Ethene $(C_2H_4)$ is an unsaturated hydrocarbon containing a double bond.Unsaturated hydrocarbons react with Baeyer's reagent (alkaline $KMnO_4$ solution) to decolorize the purple color of $KMnO_4$ due to the formation of ethylene glycol.

The gas evolved by the reaction of ethyl iodide with alcoholic $KOH$,which decolorizes basic $KMnO_4$ solution,is........

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