What is the correct order of bond strength?

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Question

(A) The bond strength is directly proportional to the bond order and the $s$-character of the hybrid orbitals involved in the bond formation.For $C-C$

Vedclass · Accepted Answer

$C-C < C=C < C \equiv C$

Vedclass · Answer

(A) The bond strength is directly proportional to the bond order and the $s$-character of the hybrid orbitals involved in the bond formation.For $C-C$ (alkane),the hybridization is $sp^3$ ($25\% \ s$-character).For $C=C$ (alkene),the hybridization is $sp^2$ ($33.3\% \ s$-character).For $C \equiv C$ (alkyne),the hybridization is $sp$ ($50\% \ s$-character).As the $s$-character increases,the bond becomes shorter and stronger.Therefore,the correct order of bond strength is $C-C < C=C < C \equiv C$.

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