$HCl$ does not follow the anti-Markovnikov rule because...

  • A
    It is a strong acid.
  • B
    It is in gaseous state.
  • C
    Its bond dissociation energy is high.
  • D
    It is in solid state.

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The major product formed during the reaction of $1$-methylcyclopentene with $CH_3CO_3H$ is

What is the major product of the following reaction?

Diimide $(N_2H_2)$ is used to reduce the double bond of:

Which of the following alkenes yield $3-$bromo$-3-$methylpentane as the major product upon addition of $HBr$?
$(I)$ $3-$methylpent$-2-$ene
$(II)$ $3-$methylpent$-2-$ene (isomer)
$(III)$ $3-$ethylpent$-1-$ene
$(IV)$ $3-$methylpent$-1-$ene

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What will be the major product of the following sequence of reactions?
$n-Bu-C \equiv CH \xrightarrow[(ii) \text{Lindlar cat.}, H_2]{(i) n-BuLi, n-C_5H_{11}Cl}$

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