What is the product of the reaction: CH_3-CH= | vedclass

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(A) The reaction of $NOCl$ (Tilden's reagent) with an alkene follows Markovnikov's rule. $NOCl$ dissociates into $NO^+$ (electrophile) and $Cl^-$ (nuc

Vedclass · Accepted Answer

$CH_3-CH(Cl)-CH_2(NO)$

Vedclass · Answer

(A) The reaction of $NOCl$ (Tilden's reagent) with an alkene follows Markovnikov's rule. $NOCl$ dissociates into $NO^+$ (electrophile) and $Cl^-$ (nucleophile). In propene $(CH_3-CH=CH_2)$,the electrophilic addition of $NO^+$ occurs at the terminal carbon $(CH_2)$ to form a more stable secondary carbocation $(CH_3-CH^+-CH_2-NO)$. Subsequently,the nucleophile $Cl^-$ attacks the carbocation to form $CH_3-CH(Cl)-CH_2(NO)$.

What is the product of the reaction: $CH_3-CH=CH_2 \xrightarrow{NOCl}$?

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