What is the product of the Friedel-Crafts rea | vedclass

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(D) The Friedel-Crafts alkylation of benzene with chloroform $(CHCl_3)$ in the presence of anhydrous $AlCl_3$ proceeds through the formation of a carb

Vedclass · Accepted Answer

All of the above

Vedclass · Answer

(D) The Friedel-Crafts alkylation of benzene with chloroform $(CHCl_3)$ in the presence of anhydrous $AlCl_3$ proceeds through the formation of a carbocation intermediate. Initially,benzene reacts with $CHCl_3$ to form benzal chloride $(C_6H_5CHCl_2)$. This intermediate further reacts with more benzene molecules via electrophilic substitution to form triphenylmethane $((C_6H_5)_3CH)$. Since the reaction continues until all chlorine atoms are replaced by phenyl groups,the final major product is triphenylmethane,but the reaction mixture contains intermediate products like $(C_6H_5)_2CHCl$ and $C_6H_5CHCl_2$ depending on the stoichiometry. Thus,all the given options represent products formed during the reaction sequence.

What is the product of the Friedel-Crafts reaction of benzene with chloroform?

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