Find the product of the reaction: $CH_3 - CH = CH_2 + HBr \rightarrow$ ?

The major product $(A)$ is:

Alkene $(A)$ will be:
$\mathop A\limits_{(\text{alkene})} \xrightarrow{RCO_3H, H_2O} \text{Racemic mixture}$
$\mathop A\limits_{(\text{alkene})} \xrightarrow{\text{Cold dil. } KMnO_4} \text{Meso-compound}$

The Diels-Alder reaction will not take place with which of the following reactants?

The reaction of $4$-methyloct$-1-$ene $(P, 2.52 \ g)$ with $HBr$ in the presence of $(C_6H_5CO_2)_2O_2$ gives two isomeric bromides in a $9:1$ ratio,with a combined yield of $50 \%$. Of these,the entire amount of the primary alkyl bromide was reacted with an appropriate amount of diethylamine followed by treatment with aqueous $K_2CO_3$ to give a non-ionic product $S$ in $100 \% $ yield. The mass (in $mg$) of $S$ obtained is. . . . . . . [Use molar mass (in $g \ mol^{-1}$) : $H=1, C=12, N=14, Br=80$]

Which of the following compounds reacts with $HBr$ to form $1$-Bromo-$1$-methylcyclohexane?